How many total atoms are in the chemical formula Mg3(PO4)2?Group of answer choices35913None of the above.

The chemical formula Mg3(PO4)2 represents a compound made up of Magnesium (Mg), Phosphorus (P), and Oxygen (O).

1. First, look at the subscript outside the parentheses, which is 2. This means that everything inside the parentheses is multiplied by 2.

2. Inside the parentheses, we have PO4. P has no subscript, so there is 1 atom of P. O has a subscript of 4, so there are 4 atoms of O.

3. Multiply the number of P and O atoms by the subscript outside the parentheses. So, there are 21 = 2 atoms of P and 24 = 8 atoms of O.

4. Outside the parentheses, we have Mg with a subscript of 3, so there are 3 atoms of Mg.

5. Add up the total number of atoms: 3 (Mg) + 2 (P) + 8 (O) = 13 atoms.

So, the correct answer is 13.